Drop a Rock from An Airplane and Hit a Target

Introduction

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ground speed = air speed - wind speed

acceleration of gravity = 32 feet/sec/sec

Something to Think About

When the rock is released, its forward velocity immediately start slowing down due to air resistance.

Also its downward velocity would be effected by air resistance until it reaches terminal velocity.

Velocity is the speed of something in a given direction. in other words, it is speed and direction.

Denser air (closer to the ground) has more air resistance.

Wind speed generally varies with altitude. Wind speed close to the ground is generally slower that wind speed at altitude.

The terrain is generally not flat. (The altitude used in the calculations may be incorrect.)

Project #1

At what distance must you drop a rock from the airplane and hit the target?

Note: Use a simplified model. Ignore air resistance, variable wind speed, uneven terrain, ...

Create a program:

1It should be velocity not speed. Direction should be included or implied. (+ or -)

Project #2 (a more complex problem)

Destroy the airplane before it can bomb the target.

Combine the project "How far will a cannon ball go? How high?" with Project #1.

Assume the target has a cannon and shoots at the airplane. If the cannon ball and airplane comes within 100 ft of each other, the airplane is assumed to be destroyed.

Note: Use a simplified model. Ignore air resistance, variable wind speed, uneven terrain, ...

Create a program:

1It should be velocity not speed. Direction should be included or implied. (+ or -)

Useful Formulas

Finds the distance traveled (d) of an object with an initial velocity of zero, acceleration (a), and time (t) traveled. The equation used is

d = ½ * a * t2

Finds the distance traveled (d) of an object with an initial velocity (v), acceleration (a), and time (t) traveled. The equation used is

d = (v * t) + (½ * a * t2)